نتائج البحث

...; dx = \int_0^\frac{\pi}{2} \sqrt{1-\sin^2(u)} \cos(u)\;du = \int_0^\frac{\pi}{2} \cos^2(u)\;du [[en:Integration by substitution]]

:<math>R_{\mu \nu} - {1 \over 2}g_{\mu \nu}\,R + g_{\mu \nu} \Lambda = {8 \pi G \over c^4} T_{\mu \nu}</math> :<math>G_{\mu \nu} = {8 \pi G \over c^4} T_{\mu \nu},</math>

: <math>v=\frac{I}{N e A}=\frac{I}{N \pi r^2 e}</math> * [http://www.cartage.org.lb/en/themes/sciences/physics/Electromagnetism/Electrostatics/ElectricCurrent/Mys

...>n</math> من الأنوية في مساحة <math>A</math> يكون احتمال التفاعل <math>(n \pi r^2)/A</math>, وهو نسبة الدوائر ذات نطف القطر <mat [[en:cross section (physics)]]

:<math>u(\lambda,T) = {8\pi h c\over \lambda^5}{1\over e^{h c/\lambda kT}-1}</math> :<math>{ \partial u \over \partial \lambda } = 8\pi h c\left({hc\over kT \lambda^7}{e^{h c/\lambda kT}\over \left(e^{h c/\lambd

:<math>\left|R\right|\leq\frac{2}{(2\pi)^p}\int_0^n\left|f^{(p)}(x)\right|\,dx.</math>

:<math>\pi = 3.14159265358979....\,</math> [[en:Number]]