نتائج البحث

:<math>u(\lambda,T) = {8\pi h c\over \lambda^5}{1\over e^{h c/\lambda kT}-1}</math> :<math>{ \partial u \over \partial \lambda } = 8\pi h c\left({hc\over kT \lambda^7}{e^{h c/\lambda kT}\over \left(e^{h c/\lambd

:<math>\pi = 3.14159265358979....\,</math> [[fr:Nombre]]

* four-pi counter * francium (fr)